Leap Year Program using Shell Scripting in Linux

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Finding Leap year in C program is very simple one, As same in Shell also we Implement on finding Leap year, I tried this in Ubuntu Linux. Saved with the extension of .sh, and i run this program by using sh <filename>. Lets try out and tell any query if there.

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[sourcecode language=’css’]
clear
echo “LEAP OR NON LEAP YEAR ”
echo “Enter the year:”
read a
if [ [$a%4] –eq 0 ]
then
echo “$a is leap year”
else
echo “$a is a non-leap year”
fi
[/sourcecode]

 

OUTPUT:

LEAP OR NON-LEAP YEAR

Enter the year: 1996

1996 is leap year

Enter the year: 2010

2010 is a non-leap year

 

Balaji

, is a computer science graduate. He is interested in sharing the system tweaking ,Web-designing, SEO and tips to use your system fetching you utmost use. Happy tweaking! :D

This Post Has One Comment

  1. tuxy

    It is not sufficient to check year mod 4 alone, this example will fail for some century years such as 1700, 1800 and 1900.

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